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200212011988433 is a prime number
BaseRepresentation
bin101101100001011101111101…
…110110101011010111010001
3222020220002012100120222110022
4231201131331312223113101
5202220233200032112213
61545452043434113225
760112561204426124
oct5541357566532721
9866802170528408
10200212011988433
115888048a284215
121a55651987b815
138793bb107c503
1437624551643bb
151822e91d51308
hexb6177ddab5d1

200212011988433 has 2 divisors, whose sum is σ = 200212011988434. Its totient is φ = 200212011988432.

The previous prime is 200212011988427. The next prime is 200212011988489. The reversal of 200212011988433 is 334889110212002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 144489847874449 + 55722164113984 = 12020393^2 + 7464728^2 .

It is a cyclic number.

It is not a de Polignac number, because 200212011988433 - 222 = 200212007794129 is a prime.

It is not a weakly prime, because it can be changed into another prime (200212011988033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100106005994216 + 100106005994217.

It is an arithmetic number, because the mean of its divisors is an integer number (100106005994217).

Almost surely, 2200212011988433 is an apocalyptic number.

It is an amenable number.

200212011988433 is a deficient number, since it is larger than the sum of its proper divisors (1).

200212011988433 is an equidigital number, since it uses as much as digits as its factorization.

200212011988433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 165888, while the sum is 44.

The spelling of 200212011988433 in words is "two hundred trillion, two hundred twelve billion, eleven million, nine hundred eighty-eight thousand, four hundred thirty-three".