Base | Representation |
---|---|
bin | 1001000110101100011001… |
… | …00101100011100101110001 |
3 | 2121220000012221022011201020 |
4 | 10203112030211203211301 |
5 | 10111011410003101001 |
6 | 110325340213530053 |
7 | 4134325013313510 |
oct | 443261445434561 |
9 | 77800187264636 |
10 | 20021201222001 |
11 | 6419a42157a11 |
12 | 22b42ab943929 |
13 | b22cb67c0105 |
14 | 4d3061cb0677 |
15 | 24abe62ce736 |
hex | 12358c963971 |
20021201222001 has 8 divisors (see below), whose sum is σ = 30508497100224. Its totient is φ = 11440686412560.
The previous prime is 20021201221999. The next prime is 20021201222027. The reversal of 20021201222001 is 10022210212002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 20021201222001 - 21 = 20021201221999 is a prime.
It is not an unprimeable number, because it can be changed into a prime (20021201222081) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 476695267170 + ... + 476695267211.
It is an arithmetic number, because the mean of its divisors is an integer number (3813562137528).
Almost surely, 220021201222001 is an apocalyptic number.
20021201222001 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
It is an amenable number.
20021201222001 is a deficient number, since it is larger than the sum of its proper divisors (10487295878223).
20021201222001 is an equidigital number, since it uses as much as digits as its factorization.
20021201222001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 953390534391.
The product of its (nonzero) digits is 64, while the sum is 15.
Adding to 20021201222001 its reverse (10022210212002), we get a palindrome (30043411434003).
The spelling of 20021201222001 in words is "twenty trillion, twenty-one billion, two hundred one million, two hundred twenty-two thousand, one".
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