Base | Representation |
---|---|
bin | 101101100001011110000011… |
… | …000110011101011111011001 |
3 | 222020220002102111020001002011 |
4 | 231201132003012131133121 |
5 | 202220233340100340433 |
6 | 1545452100300505521 |
7 | 60112563323550436 |
oct | 5541360306353731 |
9 | 866802374201064 |
10 | 200212100011993 |
11 | 58880524a35663 |
12 | 1a55654324b2a1 |
13 | 8793bc638b964 |
14 | 3762462b18b8d |
15 | 1822e9993c3cd |
hex | b6178319d7d9 |
200212100011993 has 2 divisors, whose sum is σ = 200212100011994. Its totient is φ = 200212100011992.
The previous prime is 200212100011919. The next prime is 200212100012027. The reversal of 200212100011993 is 399110001212002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 182439400182169 + 17772699829824 = 13507013^2 + 4215768^2 .
It is a cyclic number.
It is not a de Polignac number, because 200212100011993 - 217 = 200212099880921 is a prime.
It is not a weakly prime, because it can be changed into another prime (200212100051993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100106050005996 + 100106050005997.
It is an arithmetic number, because the mean of its divisors is an integer number (100106050005997).
Almost surely, 2200212100011993 is an apocalyptic number.
It is an amenable number.
200212100011993 is a deficient number, since it is larger than the sum of its proper divisors (1).
200212100011993 is an equidigital number, since it uses as much as digits as its factorization.
200212100011993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 31.
Adding to 200212100011993 its reverse (399110001212002), we get a palindrome (599322101223995).
The spelling of 200212100011993 in words is "two hundred trillion, two hundred twelve billion, one hundred million, eleven thousand, nine hundred ninety-three".
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