200212102111001 has 4 divisors (see below), whose sum is σ = 200212245453312. Its totient is φ = 200211958768692.

The previous prime is 200212102110863. The next prime is 200212102111013. The reversal of 200212102111001 is 100111201212002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-200212102111001 is a prime.

It is a super-3 number, since 3×200212102111001³ (a number of 44 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200212102111081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69555221 + ... + 72376466.

It is an arithmetic number, because the mean of its divisors is an integer number (50053061363328).

Almost surely, 2^{200212102111001} is an apocalyptic number.

It is an amenable number.

200212102111001 is a deficient number, since it is larger than the sum of its proper divisors (143342311).

200212102111001 is a wasteful number, since it uses less digits than its factorization.

200212102111001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 143342310.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 200212102111001 its reverse (100111201212002), we get a palindrome (300323303323003).

The spelling of 200212102111001 in words is "two hundred trillion, two hundred twelve billion, one hundred two million, one hundred eleven thousand, one".