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2002121202011 = 7972948632109
BaseRepresentation
bin11101001000100111101…
…110010001100101011011
321002101211021021002002112
4131020213232101211123
5230300321011431021
64131432313422535
7264435300265340
oct35104756214533
97071737232075
102002121202011
117021052502a7
1228403640aa4b
13116a50b667a8
146cc904987c7
153712e331d5b
hex1d227b9195b

2002121202011 has 8 divisors (see below), whose sum is σ = 2311727574240. Its totient is φ = 1698412094208.

The previous prime is 2002121202007. The next prime is 2002121202013. The reversal of 2002121202011 is 1102021212002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2002121202011 - 22 = 2002121202007 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2002121202013) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1474315376 + ... + 1474316733.

It is an arithmetic number, because the mean of its divisors is an integer number (288965946780).

Almost surely, 22002121202011 is an apocalyptic number.

2002121202011 is a deficient number, since it is larger than the sum of its proper divisors (309606372229).

2002121202011 is an equidigital number, since it uses as much as digits as its factorization.

2002121202011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2948632213.

The product of its (nonzero) digits is 32, while the sum is 14.

Adding to 2002121202011 its reverse (1102021212002), we get a palindrome (3104142414013).

Subtracting from 2002121202011 its reverse (1102021212002), we obtain a palindrome (900099990009).

The spelling of 2002121202011 in words is "two trillion, two billion, one hundred twenty-one million, two hundred two thousand, eleven".

Divisors: 1 7 97 679 2948632109 20640424763 286017314573 2002121202011