Base | Representation |
---|---|
bin | 1001000110101100011011… |
… | …01101100111011010001011 |
3 | 2121220000021020211212221020 |
4 | 10203112031231213122023 |
5 | 10111011424322041021 |
6 | 110325342130443523 |
7 | 4134325333010436 |
oct | 443261555473213 |
9 | 77800236755836 |
10 | 20021220112011 |
11 | 6419a5188a298 |
12 | 22b42b61335a3 |
13 | b22cba6a5231 |
14 | 4d30645ca81d |
15 | 24abe7cb17c6 |
hex | 12358db6768b |
20021220112011 has 32 divisors (see below), whose sum is σ = 27918858401280. Its totient is φ = 12738171916800.
The previous prime is 20021220112009. The next prime is 20021220112013. The reversal of 20021220112011 is 11021102212002.
It is an interprime number because it is at equal distance from previous prime (20021220112009) and next prime (20021220112013).
It is not a de Polignac number, because 20021220112011 - 21 = 20021220112009 is a prime.
It is not an unprimeable number, because it can be changed into a prime (20021220112013) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 389348260 + ... + 389399678.
It is an arithmetic number, because the mean of its divisors is an integer number (872464325040).
Almost surely, 220021220112011 is an apocalyptic number.
20021220112011 is a deficient number, since it is larger than the sum of its proper divisors (7897638289269).
20021220112011 is a wasteful number, since it uses less digits than its factorization.
20021220112011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 64147.
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 20021220112011 its reverse (11021102212002), we get a palindrome (31042322324013).
The spelling of 20021220112011 in words is "twenty trillion, twenty-one billion, two hundred twenty million, one hundred twelve thousand, eleven".
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