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2002124433 = 3667374811
BaseRepresentation
bin111011101010101…
…1111111010010001
312011112100110101210
41313111133322101
513100020440213
6530400250333
7100420530321
oct16725377221
95145313353
102002124433
119381687a1
1247a6109a9
1325ba3c31a
1414dc8d281
15bab820c3
hex7755fe91

2002124433 has 4 divisors (see below), whose sum is σ = 2669499248. Its totient is φ = 1334749620.

The previous prime is 2002124431. The next prime is 2002124489. The reversal of 2002124433 is 3344212002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2002124433 - 21 = 2002124431 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2002124431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 333687403 + ... + 333687408.

It is an arithmetic number, because the mean of its divisors is an integer number (667374812).

Almost surely, 22002124433 is an apocalyptic number.

It is an amenable number.

2002124433 is a deficient number, since it is larger than the sum of its proper divisors (667374815).

2002124433 is an equidigital number, since it uses as much as digits as its factorization.

2002124433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 667374814.

The product of its (nonzero) digits is 1152, while the sum is 21.

The square root of 2002124433 is about 44745.1051289412. The cubic root of 2002124433 is about 1260.3669950113.

Adding to 2002124433 its reverse (3344212002), we get a palindrome (5346336435).

The spelling of 2002124433 in words is "two billion, two million, one hundred twenty-four thousand, four hundred thirty-three".

Divisors: 1 3 667374811 2002124433