Base | Representation |
---|---|
bin | 11101001000101000011… |
… | …000101010001110101011 |
3 | 21002101212001011120111202 |
4 | 131020220120222032223 |
5 | 230300331333004003 |
6 | 4131433351514415 |
7 | 264435463603034 |
oct | 35105030521653 |
9 | 7071761146452 |
10 | 2002132313003 |
11 | 70211054a139 |
12 | 28403a088a0b |
13 | 116a53256c44 |
14 | 6cc91b4ba8b |
15 | 371302c9088 |
hex | 1d22862a3ab |
2002132313003 has 4 divisors (see below), whose sum is σ = 2012193279600. Its totient is φ = 1992071346408.
The previous prime is 2002132312987. The next prime is 2002132313039. The reversal of 2002132313003 is 3003132312002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2002132313003 - 24 = 2002132312987 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2002132313053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5030483000 + ... + 5030483397.
It is an arithmetic number, because the mean of its divisors is an integer number (503048319900).
Almost surely, 22002132313003 is an apocalyptic number.
2002132313003 is a deficient number, since it is larger than the sum of its proper divisors (10060966597).
2002132313003 is a wasteful number, since it uses less digits than its factorization.
2002132313003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10060966596.
The product of its (nonzero) digits is 648, while the sum is 20.
Adding to 2002132313003 its reverse (3003132312002), we get a palindrome (5005264625005).
The spelling of 2002132313003 in words is "two trillion, two billion, one hundred thirty-two million, three hundred thirteen thousand, three".
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