Base | Representation |
---|---|
bin | 11101001000101000011… |
… | …100001010011001101011 |
3 | 21002101212002220020001110 |
4 | 131020220130022121223 |
5 | 230300332101344321 |
6 | 4131433423321403 |
7 | 264435504446031 |
oct | 35105034123153 |
9 | 7071762806043 |
10 | 2002133231211 |
11 | 702111016a93 |
12 | 28403a450263 |
13 | 116a534b8b69 |
14 | 6cc91d0a551 |
15 | 3713040b176 |
hex | 1d22870a66b |
2002133231211 has 4 divisors (see below), whose sum is σ = 2669510974952. Its totient is φ = 1334755487472.
The previous prime is 2002133231099. The next prime is 2002133231353. The reversal of 2002133231211 is 1121323312002.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 2002133231211 - 27 = 2002133231083 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2002133231011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 333688871866 + ... + 333688871871.
It is an arithmetic number, because the mean of its divisors is an integer number (667377743738).
Almost surely, 22002133231211 is an apocalyptic number.
2002133231211 is a deficient number, since it is larger than the sum of its proper divisors (667377743741).
2002133231211 is an equidigital number, since it uses as much as digits as its factorization.
2002133231211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 667377743740.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 2002133231211 its reverse (1121323312002), we get a palindrome (3123456543213).
The spelling of 2002133231211 in words is "two trillion, two billion, one hundred thirty-three million, two hundred thirty-one thousand, two hundred eleven".
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