200214003011313 has 4 divisors (see below), whose sum is σ = 266952004015088. Its totient is φ = 133476002007540.

The previous prime is 200214003011299. The next prime is 200214003011357. The reversal of 200214003011313 is 313110300412002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 200214003011313 - 2¹⁶ = 200214002945777 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 200214003011313.

It is not an unprimeable number, because it can be changed into a prime (200214007011313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33369000501883 + ... + 33369000501888.

It is an arithmetic number, because the mean of its divisors is an integer number (66738001003772).

Almost surely, 2^{200214003011313} is an apocalyptic number.

It is an amenable number.

200214003011313 is a deficient number, since it is larger than the sum of its proper divisors (66738001003775).

200214003011313 is an equidigital number, since it uses as much as digits as its factorization.

200214003011313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66738001003774.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 200214003011313 its reverse (313110300412002), we get a palindrome (513324303423315).

The spelling of 200214003011313 in words is "two hundred trillion, two hundred fourteen billion, three million, eleven thousand, three hundred thirteen".