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200215842084113 is a prime number
BaseRepresentation
bin101101100001100001100010…
…001001010101010100010001
3222020220110002021120222222212
4231201201202021111110101
5202220314021033142423
61545453515454241505
760113055132622622
oct5541414211252421
9866813067528885
10200215842084113
1158882075270849
121a5572084b6295
13879437172330b
1437626d9acba49
151823118214578
hexb61862255511

200215842084113 has 2 divisors, whose sum is σ = 200215842084114. Its totient is φ = 200215842084112.

The previous prime is 200215842084079. The next prime is 200215842084149. The reversal of 200215842084113 is 311480248512002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 182308108631104 + 17907733453009 = 13502152^2 + 4231753^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200215842084113 is a prime.

It is not a weakly prime, because it can be changed into another prime (200215842084613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100107921042056 + 100107921042057.

It is an arithmetic number, because the mean of its divisors is an integer number (100107921042057).

Almost surely, 2200215842084113 is an apocalyptic number.

It is an amenable number.

200215842084113 is a deficient number, since it is larger than the sum of its proper divisors (1).

200215842084113 is an equidigital number, since it uses as much as digits as its factorization.

200215842084113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 122880, while the sum is 41.

The spelling of 200215842084113 in words is "two hundred trillion, two hundred fifteen billion, eight hundred forty-two million, eighty-four thousand, one hundred thirteen".