Base | Representation |
---|---|
bin | 11101001000101100100… |
… | …010111111111001000011 |
3 | 21002102000220112202012211 |
4 | 131020230202333321003 |
5 | 230301002221211120 |
6 | 4131444324202551 |
7 | 264440302214050 |
oct | 35105442777103 |
9 | 7072026482184 |
10 | 2002202132035 |
11 | 7021469a7216 |
12 | 284059539457 |
13 | 116a64861291 |
14 | 6cc9b124027 |
15 | 371364bb25a |
hex | 1d22c8bfe43 |
2002202132035 has 16 divisors (see below), whose sum is σ = 2748202310592. Its totient is φ = 1371776054400.
The previous prime is 2002202131987. The next prime is 2002202132087. The reversal of 2002202132035 is 5302312022002.
It is not a de Polignac number, because 2002202132035 - 215 = 2002202099267 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2002202131997 and 2002202132015.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24177876 + ... + 24260545.
It is an arithmetic number, because the mean of its divisors is an integer number (171762644412).
Almost surely, 22002202132035 is an apocalyptic number.
2002202132035 is a deficient number, since it is larger than the sum of its proper divisors (746000178557).
2002202132035 is a wasteful number, since it uses less digits than its factorization.
2002202132035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48439614.
The product of its (nonzero) digits is 1440, while the sum is 22.
Adding to 2002202132035 its reverse (5302312022002), we get a palindrome (7304514154037).
The spelling of 2002202132035 in words is "two trillion, two billion, two hundred two million, one hundred thirty-two thousand, thirty-five".
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