Base | Representation |
---|---|
bin | 11101001000101101000… |
… | …110000101110010000011 |
3 | 21002102001112212010002202 |
4 | 131020231012011302003 |
5 | 230301012100044303 |
6 | 4131445253303415 |
7 | 264440443336556 |
oct | 35105506056203 |
9 | 7072045763082 |
10 | 2002211331203 |
11 | 70215110a736 |
12 | 284060634b6b |
13 | 116a66732485 |
14 | 6cc9c43a69d |
15 | 371371d6c88 |
hex | 1d22d185c83 |
2002211331203 has 4 divisors (see below), whose sum is σ = 2002632765408. Its totient is φ = 2001789897000.
The previous prime is 2002211331199. The next prime is 2002211331217. The reversal of 2002211331203 is 3021331122002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2002211331203 - 22 = 2002211331199 is a prime.
It is a super-2 number, since 2×20022113312032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2002211331403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 210709976 + ... + 210719477.
It is an arithmetic number, because the mean of its divisors is an integer number (500658191352).
Almost surely, 22002211331203 is an apocalyptic number.
2002211331203 is a deficient number, since it is larger than the sum of its proper divisors (421434205).
2002211331203 is an equidigital number, since it uses as much as digits as its factorization.
2002211331203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 421434204.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 2002211331203 its reverse (3021331122002), we get a palindrome (5023542453205).
The spelling of 2002211331203 in words is "two trillion, two billion, two hundred eleven million, three hundred thirty-one thousand, two hundred three".
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