Base | Representation |
---|---|
bin | 101101100001100111011101… |
… | …001011011011110110001011 |
3 | 222020221001111110101120001220 |
4 | 231201213131023123312023 |
5 | 202220420032001400021 |
6 | 1545500450500213123 |
7 | 60113401540333254 |
oct | 5541473513336613 |
9 | 866831443346056 |
10 | 200222201200011 |
11 | 58884838882731 |
12 | 1a5584a209a1a3 |
13 | 8794b460175a3 |
14 | 3762b4049bb2b |
15 | 182338b636cc6 |
hex | b619dd2dbd8b |
200222201200011 has 4 divisors (see below), whose sum is σ = 266962934933352. Its totient is φ = 133481467466672.
The previous prime is 200222201200003. The next prime is 200222201200057. The reversal of 200222201200011 is 110002102222002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 200222201200011 - 23 = 200222201200003 is a prime.
It is not an unprimeable number, because it can be changed into a prime (200222201200061) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33370366866666 + ... + 33370366866671.
It is an arithmetic number, because the mean of its divisors is an integer number (66740733733338).
Almost surely, 2200222201200011 is an apocalyptic number.
200222201200011 is a deficient number, since it is larger than the sum of its proper divisors (66740733733341).
200222201200011 is an equidigital number, since it uses as much as digits as its factorization.
200222201200011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66740733733340.
The product of its (nonzero) digits is 64, while the sum is 15.
Adding to 200222201200011 its reverse (110002102222002), we get a palindrome (310224303422013).
The spelling of 200222201200011 in words is "two hundred trillion, two hundred twenty-two billion, two hundred one million, two hundred thousand, eleven".
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