200223214031131 has 4 divisors (see below), whose sum is σ = 200223250757064. Its totient is φ = 200223177305200.

The previous prime is 200223214031081. The next prime is 200223214031149. The reversal of 200223214031131 is 131130412322002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200223214031131 - 2¹³ = 200223214022939 is a prime.

It is a super-2 number, since 2×200223214031131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200223214031096 and 200223214031105.

It is not an unprimeable number, because it can be changed into a prime (200223214031231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8373985 + ... + 21692626.

It is an arithmetic number, because the mean of its divisors is an integer number (50055812689266).

Almost surely, 2^{200223214031131} is an apocalyptic number.

200223214031131 is a deficient number, since it is larger than the sum of its proper divisors (36725933).

200223214031131 is an equidigital number, since it uses as much as digits as its factorization.

200223214031131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36725932.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 200223214031131 its reverse (131130412322002), we get a palindrome (331353626353133).

The spelling of 200223214031131 in words is "two hundred trillion, two hundred twenty-three billion, two hundred fourteen million, thirty-one thousand, one hundred thirty-one".