Base | Representation |
---|---|
bin | 11101001000110010011… |
… | …100101001010100010011 |
3 | 21002102021210211100220020 |
4 | 131020302130221110103 |
5 | 230301203042130003 |
6 | 4131502222114523 |
7 | 264442613533626 |
oct | 35106234512423 |
9 | 7072253740806 |
10 | 2002301130003 |
11 | 702197873919 |
12 | 28408671ba43 |
13 | 116a7c213965 |
14 | 6ccaa333dbd |
15 | 37140023d53 |
hex | 1d232729513 |
2002301130003 has 8 divisors (see below), whose sum is σ = 2673786033600. Its totient is φ = 1332841823208.
The previous prime is 2002301129971. The next prime is 2002301130077. The reversal of 2002301130003 is 3000311032002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2002301130003 - 25 = 2002301129971 is a prime.
It is a super-2 number, since 2×20023011300032 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2002301138003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 506396893 + ... + 506400846.
It is an arithmetic number, because the mean of its divisors is an integer number (334223254200).
Almost surely, 22002301130003 is an apocalyptic number.
2002301130003 is a deficient number, since it is larger than the sum of its proper divisors (671484903597).
2002301130003 is a wasteful number, since it uses less digits than its factorization.
2002301130003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1012798401.
The product of its (nonzero) digits is 108, while the sum is 15.
Adding to 2002301130003 its reverse (3000311032002), we get a palindrome (5002612162005).
The spelling of 2002301130003 in words is "two trillion, two billion, three hundred one million, one hundred thirty thousand, three".
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