Base | Representation |
---|---|
bin | 101101100001101111110000… |
… | …110110111010101110111110 |
3 | 222020221220112010010121102220 |
4 | 231201233300312322232332 |
5 | 202221041314023103124 |
6 | 1545504523545030210 |
7 | 60114135563050011 |
oct | 5541576066725676 |
9 | 866856463117386 |
10 | 200231121300414 |
11 | 588885a5a61136 |
12 | 1a55a171485366 |
13 | 87959380710c9 |
14 | 3763349035378 |
15 | 182370e7ce879 |
hex | b61bf0dbabbe |
200231121300414 has 64 divisors (see below), whose sum is σ = 407095959836160. Its totient is φ = 65642708880000.
The previous prime is 200231121300403. The next prime is 200231121300421. The reversal of 200231121300414 is 414003121132002.
It is a super-2 number, since 2×2002311213004142 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3309082792 + ... + 3309143300.
It is an arithmetic number, because the mean of its divisors is an integer number (6360874372440).
Almost surely, 2200231121300414 is an apocalyptic number.
200231121300414 is an abundant number, since it is smaller than the sum of its proper divisors (206864838535746).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
200231121300414 is a wasteful number, since it uses less digits than its factorization.
200231121300414 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 79457.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 200231121300414 its reverse (414003121132002), we get a palindrome (614234242432416).
The spelling of 200231121300414 in words is "two hundred trillion, two hundred thirty-one billion, one hundred twenty-one million, three hundred thousand, four hundred fourteen".
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