Base | Representation |
---|---|
bin | 11101001000110011110… |
… | …000011101000111010001 |
3 | 21002102100100011120020000 |
4 | 131020303300131013101 |
5 | 230301224203200423 |
6 | 4131504325040213 |
7 | 264443301346500 |
oct | 35106360350721 |
9 | 7072310146200 |
10 | 2002323100113 |
11 | 7021a920a336 |
12 | 284091b56069 |
13 | 116a83936a1b |
14 | 6ccad212837 |
15 | 37141e13843 |
hex | 1d233c1d1d1 |
2002323100113 has 60 divisors (see below), whose sum is σ = 3560389755120. Its totient is φ = 1117575588528.
The previous prime is 2002323100081. The next prime is 2002323100123. The reversal of 2002323100113 is 3110013232002.
It is not a de Polignac number, because 2002323100113 - 25 = 2002323100081 is a prime.
It is a super-2 number, since 2×20023231001132 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2002323100123) by changing a digit.
It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 5695503 + ... + 6036836.
It is an arithmetic number, because the mean of its divisors is an integer number (59339829252).
Almost surely, 22002323100113 is an apocalyptic number.
It is an amenable number.
2002323100113 is a deficient number, since it is larger than the sum of its proper divisors (1558066655007).
2002323100113 is a wasteful number, since it uses less digits than its factorization.
2002323100113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11732408 (or 11732392 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 2002323100113 its reverse (3110013232002), we get a palindrome (5112336332115).
The spelling of 2002323100113 in words is "two trillion, two billion, three hundred twenty-three million, one hundred thousand, one hundred thirteen".
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