2002323131113 has 4 divisors (see below), whose sum is σ = 2002538606148. Its totient is φ = 2002107656080.

The previous prime is 2002323131087. The next prime is 2002323131153. The reversal of 2002323131113 is 3111313232002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 870763323609 + 1131559807504 = 933147^2 + 1063748^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2002323131113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2002323131153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107723578 + ... + 107742163.

It is an arithmetic number, because the mean of its divisors is an integer number (500634651537).

Almost surely, 2^{2002323131113} is an apocalyptic number.

It is an amenable number.

2002323131113 is a deficient number, since it is larger than the sum of its proper divisors (215475035).

2002323131113 is an equidigital number, since it uses as much as digits as its factorization.

2002323131113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 215475034.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 2002323131113 its reverse (3111313232002), we get a palindrome (5113636363115).

The spelling of 2002323131113 in words is "two trillion, two billion, three hundred twenty-three million, one hundred thirty-one thousand, one hundred thirteen".