2002323134113 has 2 divisors, whose sum is σ = 2002323134114. Its totient is φ = 2002323134112.

The previous prime is 2002323134081. The next prime is 2002323134137. The reversal of 2002323134113 is 3114313232002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1996987269904 + 5335864209 = 1413148^2 + 73047^2 .

It is a cyclic number.

It is not a de Polignac number, because 2002323134113 - 2⁵ = 2002323134081 is a prime.

It is not a weakly prime, because it can be changed into another prime (2002323134183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001161567056 + 1001161567057.

It is an arithmetic number, because the mean of its divisors is an integer number (1001161567057).

Almost surely, 2^{2002323134113} is an apocalyptic number.

It is an amenable number.

2002323134113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2002323134113 is an equidigital number, since it uses as much as digits as its factorization.

2002323134113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 2002323134113 its reverse (3114313232002), we get a palindrome (5116636366115).

The spelling of 2002323134113 in words is "two trillion, two billion, three hundred twenty-three million, one hundred thirty-four thousand, one hundred thirteen".