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200233303131 = 366744434377
BaseRepresentation
bin1011101001111011010…
…1011011110001011011
3201010211121021201020010
42322132311123301123
511240034211200011
6231552542333003
720315652665031
oct2723665336133
9633747251203
10200233303131
1177a11530304
123298188a163
1315b60766a74
149997092551
15531dbab1a6
hex2e9ed5bc5b

200233303131 has 4 divisors (see below), whose sum is σ = 266977737512. Its totient is φ = 133488868752.

The previous prime is 200233303117. The next prime is 200233303139. The reversal of 200233303131 is 131303332002.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 200233303131 - 27 = 200233303003 is a prime.

It is a super-2 number, since 2×2002333031312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200233303098 and 200233303107.

It is not an unprimeable number, because it can be changed into a prime (200233303139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33372217186 + ... + 33372217191.

It is an arithmetic number, because the mean of its divisors is an integer number (66744434378).

Almost surely, 2200233303131 is an apocalyptic number.

200233303131 is a deficient number, since it is larger than the sum of its proper divisors (66744434381).

200233303131 is an equidigital number, since it uses as much as digits as its factorization.

200233303131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66744434380.

The product of its (nonzero) digits is 972, while the sum is 21.

Adding to 200233303131 its reverse (131303332002), we get a palindrome (331536635133).

The spelling of 200233303131 in words is "two hundred billion, two hundred thirty-three million, three hundred three thousand, one hundred thirty-one".

Divisors: 1 3 66744434377 200233303131