Base | Representation |
---|---|
bin | 101101100001110010000010… |
… | …100001010101011011110111 |
3 | 222020222010211102121022101212 |
4 | 231201302002201111123313 |
5 | 202221111320132204101 |
6 | 1545510010244312035 |
7 | 60114253256123150 |
oct | 5541620241253367 |
9 | 866863742538355 |
10 | 200233565116151 |
11 | 5888963a480066 |
12 | 1a55a7339a261b |
13 | 8795c3745b318 |
14 | 37634db81c927 |
15 | 182380410d1bb |
hex | b61c828556f7 |
200233565116151 has 16 divisors (see below), whose sum is σ = 229307758434048. Its totient is φ = 171276731539200.
The previous prime is 200233565116147. The next prime is 200233565116177. The reversal of 200233565116151 is 151611565332002.
200233565116151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 200233565116151 - 22 = 200233565116147 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 200233565116099 and 200233565116108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200233565116951) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 259290116 + ... + 260061206.
It is an arithmetic number, because the mean of its divisors is an integer number (14331734902128).
Almost surely, 2200233565116151 is an apocalyptic number.
200233565116151 is a deficient number, since it is larger than the sum of its proper divisors (29074193317897).
200233565116151 is an equidigital number, since it uses as much as digits as its factorization.
200233565116151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 847142.
The product of its (nonzero) digits is 162000, while the sum is 41.
The spelling of 200233565116151 in words is "two hundred trillion, two hundred thirty-three billion, five hundred sixty-five million, one hundred sixteen thousand, one hundred fifty-one".
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