Base | Representation |
---|---|
bin | 10010101001011111… |
… | …011010100111000011 |
3 | 1220200110122212021212 |
4 | 102221133122213003 |
5 | 312002001013042 |
6 | 13110524040335 |
7 | 1306125360224 |
oct | 225137324703 |
9 | 56613585255 |
10 | 20023454147 |
11 | 8545799514 |
12 | 3a699930ab |
13 | 1b714ca328 |
14 | d7d46d24b |
15 | 7c2d50482 |
hex | 4a97da9c3 |
20023454147 has 4 divisors (see below), whose sum is σ = 20023848096. Its totient is φ = 20023060200.
The previous prime is 20023454137. The next prime is 20023454179. The reversal of 20023454147 is 74145432002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20023454147 - 26 = 20023454083 is a prime.
It is a super-2 number, since 2×200234541472 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20023454107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107048 + ... + 226949.
It is an arithmetic number, because the mean of its divisors is an integer number (5005962024).
Almost surely, 220023454147 is an apocalyptic number.
20023454147 is a deficient number, since it is larger than the sum of its proper divisors (393949).
20023454147 is an equidigital number, since it uses as much as digits as its factorization.
20023454147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 393948.
The product of its (nonzero) digits is 26880, while the sum is 32.
Adding to 20023454147 its reverse (74145432002), we get a palindrome (94168886149).
The spelling of 20023454147 in words is "twenty billion, twenty-three million, four hundred fifty-four thousand, one hundred forty-seven".
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