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20024444113 = 87877227869
BaseRepresentation
bin10010101001100011…
…001100010011010001
31220200112112011021021
4102221203030103101
5312002224202423
613111001155441
71306136652352
oct225143142321
956615464237
1020024444113
118546305273
123a6a18bb81
131b71785acb
14d7d649d29
157c2e9895d
hex4a98cc4d1

20024444113 has 4 divisors (see below), whose sum is σ = 20024759860. Its totient is φ = 20024128368.

The previous prime is 20024444093. The next prime is 20024444149. The reversal of 20024444113 is 31144442002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7131295809 + 12893148304 = 84447^2 + 113548^2 .

It is a cyclic number.

It is not a de Polignac number, because 20024444113 - 229 = 19487573201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20024454113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26058 + ... + 201811.

It is an arithmetic number, because the mean of its divisors is an integer number (5006189965).

Almost surely, 220024444113 is an apocalyptic number.

It is an amenable number.

20024444113 is a deficient number, since it is larger than the sum of its proper divisors (315747).

20024444113 is an equidigital number, since it uses as much as digits as its factorization.

20024444113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 315746.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 20024444113 its reverse (31144442002), we get a palindrome (51168886115).

The spelling of 20024444113 in words is "twenty billion, twenty-four million, four hundred forty-four thousand, one hundred thirteen".

Divisors: 1 87877 227869 20024444113