Base | Representation |
---|---|
bin | 11101001001100010001… |
… | …111111111111011011001 |
3 | 21002111100200220201212200 |
4 | 131021202033333323121 |
5 | 230304323344333423 |
6 | 4132113551400413 |
7 | 264501522412263 |
oct | 35114217777331 |
9 | 7074320821780 |
10 | 2003103121113 |
11 | 702569544696 |
12 | 28426b223109 |
13 | 116b79412c03 |
14 | 6cd44a5ab33 |
15 | 3718a640d43 |
hex | 1d2623ffed9 |
2003103121113 has 12 divisors (see below), whose sum is σ = 2893458467328. Its totient is φ = 1335361791960.
The previous prime is 2003103121039. The next prime is 2003103121139. The reversal of 2003103121113 is 3111213013002.
2003103121113 is a `hidden beast` number, since 20 + 0 + 310 + 312 + 11 + 13 = 666.
It is not a de Polignac number, because 2003103121113 - 210 = 2003103120089 is a prime.
It is a super-2 number, since 2×20031031211132 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2003103121813) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3040945 + ... + 3640542.
It is an arithmetic number, because the mean of its divisors is an integer number (241121538944).
Almost surely, 22003103121113 is an apocalyptic number.
It is an amenable number.
2003103121113 is a deficient number, since it is larger than the sum of its proper divisors (890355346215).
2003103121113 is a wasteful number, since it uses less digits than its factorization.
2003103121113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6714804 (or 6714801 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 2003103121113 its reverse (3111213013002), we get a palindrome (5114316134115).
The spelling of 2003103121113 in words is "two trillion, three billion, one hundred three million, one hundred twenty-one thousand, one hundred thirteen".
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