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200311021411 = 1908110497931
BaseRepresentation
bin1011101010001101110…
…1111001111101100011
3201011001000112012122221
42322203131321331203
511240214110141121
6232004400211511
720320615405654
oct2724335717543
9634030465587
10200311021411
1177a51393196
12329a3909b97
1315b738a8707
1499a352352b
15532590db41
hex2ea3779f63

200311021411 has 4 divisors (see below), whose sum is σ = 200321538424. Its totient is φ = 200300504400.

The previous prime is 200311021409. The next prime is 200311021439. The reversal of 200311021411 is 114120113002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200311021411 - 21 = 200311021409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200311021451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5229885 + ... + 5268046.

It is an arithmetic number, because the mean of its divisors is an integer number (50080384606).

Almost surely, 2200311021411 is an apocalyptic number.

200311021411 is a deficient number, since it is larger than the sum of its proper divisors (10517013).

200311021411 is a wasteful number, since it uses less digits than its factorization.

200311021411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10517012.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 200311021411 its reverse (114120113002), we get a palindrome (314431134413).

The spelling of 200311021411 in words is "two hundred billion, three hundred eleven million, twenty-one thousand, four hundred eleven".

Divisors: 1 19081 10497931 200311021411