200311130113 has 4 divisors (see below), whose sum is σ = 201752217520. Its totient is φ = 198870042708.

The previous prime is 200311130081. The next prime is 200311130119. The reversal of 200311130113 is 311031113002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311031113002 = 2 ⋅155515556501.

It is a cyclic number.

It is not a de Polignac number, because 200311130113 - 2⁵ = 200311130081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200311130119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 720543495 + ... + 720543772.

It is an arithmetic number, because the mean of its divisors is an integer number (50438054380).

Almost surely, 2^200311130113 is an apocalyptic number.

It is an amenable number.

200311130113 is a deficient number, since it is larger than the sum of its proper divisors (1441087407).

200311130113 is a wasteful number, since it uses less digits than its factorization.

200311130113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1441087406.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 200311130113 its reverse (311031113002), we get a palindrome (511342243115).

The spelling of 200311130113 in words is "two hundred billion, three hundred eleven million, one hundred thirty thousand, one hundred thirteen".