Base | Representation |
---|---|
bin | 101101100010111011001100… |
… | …001010101110011110111011 |
3 | 222021020122120100212122200221 |
4 | 231202323030022232132323 |
5 | 202223403200142132442 |
6 | 1550010040224240511 |
7 | 60123033552444151 |
oct | 5542731412563673 |
9 | 867218510778627 |
10 | 200312110114747 |
11 | 58909986041044 |
12 | 1a5719b4470137 |
13 | 87a0473cc7957 |
14 | 376722d2493d1 |
15 | 182589e9c0467 |
hex | b62ecc2ae7bb |
200312110114747 has 2 divisors, whose sum is σ = 200312110114748. Its totient is φ = 200312110114746.
The previous prime is 200312110114693. The next prime is 200312110114757. The reversal of 200312110114747 is 747411011213002.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-200312110114747 is a prime.
It is not a weakly prime, because it can be changed into another prime (200312110114757) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100156055057373 + 100156055057374.
It is an arithmetic number, because the mean of its divisors is an integer number (100156055057374).
Almost surely, 2200312110114747 is an apocalyptic number.
200312110114747 is a deficient number, since it is larger than the sum of its proper divisors (1).
200312110114747 is an equidigital number, since it uses as much as digits as its factorization.
200312110114747 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9408, while the sum is 34.
Adding to 200312110114747 its reverse (747411011213002), we get a palindrome (947723121327749).
The spelling of 200312110114747 in words is "two hundred trillion, three hundred twelve billion, one hundred ten million, one hundred fourteen thousand, seven hundred forty-seven".
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