Base | Representation |
---|---|
bin | 11101001001100011010… |
… | …100101100111011100001 |
3 | 21002111101221210202010011 |
4 | 131021203110230323201 |
5 | 230304343002144413 |
6 | 4132115433404521 |
7 | 264502131453025 |
oct | 35114324547341 |
9 | 7074357722104 |
10 | 2003121131233 |
11 | 702578725992 |
12 | 284275269741 |
13 | 116b8007a6a1 |
14 | 6cd471c8385 |
15 | 3718beec33d |
hex | 1d26352cee1 |
2003121131233 has 4 divisors (see below), whose sum is σ = 2003743028628. Its totient is φ = 2002499233840.
The previous prime is 2003121131213. The next prime is 2003121131293. The reversal of 2003121131233 is 3321311213002.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 599768155809 + 1403352975424 = 774447^2 + 1184632^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2003121131233 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2003121131213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 310943866 + ... + 310950307.
It is an arithmetic number, because the mean of its divisors is an integer number (500935757157).
Almost surely, 22003121131233 is an apocalyptic number.
It is an amenable number.
2003121131233 is a deficient number, since it is larger than the sum of its proper divisors (621897395).
2003121131233 is an equidigital number, since it uses as much as digits as its factorization.
2003121131233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 621897394.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 2003121131233 its reverse (3321311213002), we get a palindrome (5324432344235).
The spelling of 2003121131233 in words is "two trillion, three billion, one hundred twenty-one million, one hundred thirty-one thousand, two hundred thirty-three".
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