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2003122483 is a prime number
BaseRepresentation
bin111011101100101…
…0011100100110011
312011121020011110121
41313121103210303
513100244404413
6530433511111
7100432155145
oct16731234463
95147204417
102003122483
1193878a62a
1247aa12497
1325bccb69b
1415006cc95
15bacccb8d
hex77653933

2003122483 has 2 divisors, whose sum is σ = 2003122484. Its totient is φ = 2003122482.

The previous prime is 2003122399. The next prime is 2003122493. The reversal of 2003122483 is 3842213002.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2003122483 is a prime.

It is not a weakly prime, because it can be changed into another prime (2003122493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001561241 + 1001561242.

It is an arithmetic number, because the mean of its divisors is an integer number (1001561242).

Almost surely, 22003122483 is an apocalyptic number.

2003122483 is a deficient number, since it is larger than the sum of its proper divisors (1).

2003122483 is an equidigital number, since it uses as much as digits as its factorization.

2003122483 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

The square root of 2003122483 is about 44756.2563559554. The cubic root of 2003122483 is about 1260.5763893087.

Adding to 2003122483 its reverse (3842213002), we get a palindrome (5845335485).

The spelling of 2003122483 in words is "two billion, three million, one hundred twenty-two thousand, four hundred eighty-three".