Base | Representation |
---|---|
bin | 101101100010111011011000… |
… | …000101101100011000011011 |
3 | 222021020200002022020002002101 |
4 | 231202323120011230120123 |
5 | 202223404102342401021 |
6 | 1550010112131144231 |
7 | 60123041531461543 |
oct | 5542733005543033 |
9 | 867220068202071 |
10 | 200312310122011 |
11 | 58909a78a294aa |
12 | 1a571a4b445077 |
13 | 87a04a6585349 |
14 | 376724ba30323 |
15 | 18258b232ba91 |
hex | b62ed816c61b |
200312310122011 has 2 divisors, whose sum is σ = 200312310122012. Its totient is φ = 200312310122010.
The previous prime is 200312310121999. The next prime is 200312310122053. The reversal of 200312310122011 is 110221013213002.
200312310122011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200312310122011 - 223 = 200312301733403 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 200312310122011.
It is not a weakly prime, because it can be changed into another prime (200312310122081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100156155061005 + 100156155061006.
It is an arithmetic number, because the mean of its divisors is an integer number (100156155061006).
Almost surely, 2200312310122011 is an apocalyptic number.
200312310122011 is a deficient number, since it is larger than the sum of its proper divisors (1).
200312310122011 is an equidigital number, since it uses as much as digits as its factorization.
200312310122011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 200312310122011 its reverse (110221013213002), we get a palindrome (310533323335013).
The spelling of 200312310122011 in words is "two hundred trillion, three hundred twelve billion, three hundred ten million, one hundred twenty-two thousand, eleven".
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