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200312310122011 is a prime number
BaseRepresentation
bin101101100010111011011000…
…000101101100011000011011
3222021020200002022020002002101
4231202323120011230120123
5202223404102342401021
61550010112131144231
760123041531461543
oct5542733005543033
9867220068202071
10200312310122011
1158909a78a294aa
121a571a4b445077
1387a04a6585349
14376724ba30323
1518258b232ba91
hexb62ed816c61b

200312310122011 has 2 divisors, whose sum is σ = 200312310122012. Its totient is φ = 200312310122010.

The previous prime is 200312310121999. The next prime is 200312310122053. The reversal of 200312310122011 is 110221013213002.

200312310122011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 200312310122011 - 223 = 200312301733403 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 200312310122011.

It is not a weakly prime, because it can be changed into another prime (200312310122081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100156155061005 + 100156155061006.

It is an arithmetic number, because the mean of its divisors is an integer number (100156155061006).

Almost surely, 2200312310122011 is an apocalyptic number.

200312310122011 is a deficient number, since it is larger than the sum of its proper divisors (1).

200312310122011 is an equidigital number, since it uses as much as digits as its factorization.

200312310122011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 200312310122011 its reverse (110221013213002), we get a palindrome (310533323335013).

The spelling of 200312310122011 in words is "two hundred trillion, three hundred twelve billion, three hundred ten million, one hundred twenty-two thousand, eleven".