Base | Representation |
---|---|
bin | 1011101010001110010… |
… | …1100100111001011001 |
3 | 201011001011022101001121 |
4 | 2322203211210321121 |
5 | 11240220114013111 |
6 | 232004511245241 |
7 | 20320641452365 |
oct | 2724345447131 |
9 | 634034271047 |
10 | 200313032281 |
11 | 77a52536a6a |
12 | 329a4519821 |
13 | 15b74130a8b |
14 | 99a38c82a5 |
15 | 5325ba9871 |
hex | 2ea3964e59 |
200313032281 has 2 divisors, whose sum is σ = 200313032282. Its totient is φ = 200313032280.
The previous prime is 200313032167. The next prime is 200313032291. The reversal of 200313032281 is 182230313002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 174340486681 + 25972545600 = 417541^2 + 161160^2 .
It is a cyclic number.
It is not a de Polignac number, because 200313032281 - 29 = 200313031769 is a prime.
It is a super-2 number, since 2×2003130322812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (200313032291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100156516140 + 100156516141.
It is an arithmetic number, because the mean of its divisors is an integer number (100156516141).
Almost surely, 2200313032281 is an apocalyptic number.
It is an amenable number.
200313032281 is a deficient number, since it is larger than the sum of its proper divisors (1).
200313032281 is an equidigital number, since it uses as much as digits as its factorization.
200313032281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 200313032281 its reverse (182230313002), we get a palindrome (382543345283).
The spelling of 200313032281 in words is "two hundred billion, three hundred thirteen million, thirty-two thousand, two hundred eighty-one".
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