Base | Representation |
---|---|
bin | 11101001001100011111… |
… | …010110001111010010111 |
3 | 21002111102122120212200100 |
4 | 131021203322301322113 |
5 | 230304403031104421 |
6 | 4132120431345143 |
7 | 264502312345512 |
oct | 35114372617227 |
9 | 7074378525610 |
10 | 2003131113111 |
11 | 702583323477 |
12 | 2842786821b3 |
13 | 116b82163c1b |
14 | 6cd48665d79 |
15 | 3718cd1ec26 |
hex | 1d263eb1e97 |
2003131113111 has 96 divisors (see below), whose sum is σ = 3115187712000. Its totient is φ = 1237529664000.
The previous prime is 2003131113103. The next prime is 2003131113119. The reversal of 2003131113111 is 1113111313002.
2003131113111 is a `hidden beast` number, since 200 + 31 + 311 + 13 + 111 = 666.
It is an interprime number because it is at equal distance from previous prime (2003131113103) and next prime (2003131113119).
It is not a de Polignac number, because 2003131113111 - 23 = 2003131113103 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2003131113119) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1244953275 + ... + 1244954883.
It is an arithmetic number, because the mean of its divisors is an integer number (32449872000).
Almost surely, 22003131113111 is an apocalyptic number.
2003131113111 is a deficient number, since it is larger than the sum of its proper divisors (1112056598889).
2003131113111 is a wasteful number, since it uses less digits than its factorization.
2003131113111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2845 (or 2842 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 2003131113111 its reverse (1113111313002), we get a palindrome (3116242426113).
The spelling of 2003131113111 in words is "two trillion, three billion, one hundred thirty-one million, one hundred thirteen thousand, one hundred eleven".
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