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2003201323 = 4334626331
BaseRepresentation
bin111011101100110…
…0110110100101011
312011121101011121121
41313121212310223
513100304420243
6530435320111
7100432634044
oct16731466453
95147334547
102003201323
11938833892
1247aa50037
1325c028536
1415008d8cb
15bace61ed
hex77666d2b

2003201323 has 4 divisors (see below), whose sum is σ = 2007828088. Its totient is φ = 1998574560.

The previous prime is 2003201297. The next prime is 2003201327. The reversal of 2003201323 is 3231023002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2003201323 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2003201297 and 2003201306.

It is not an unprimeable number, because it can be changed into a prime (2003201327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2312733 + ... + 2313598.

It is an arithmetic number, because the mean of its divisors is an integer number (501957022).

Almost surely, 22003201323 is an apocalyptic number.

2003201323 is a deficient number, since it is larger than the sum of its proper divisors (4626765).

2003201323 is an equidigital number, since it uses as much as digits as its factorization.

2003201323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4626764.

The product of its (nonzero) digits is 216, while the sum is 16.

The square root of 2003201323 is about 44757.1371180061. The cubic root of 2003201323 is about 1260.5929272454.

Adding to 2003201323 its reverse (3231023002), we get a palindrome (5234224325).

The spelling of 2003201323 in words is "two billion, three million, two hundred one thousand, three hundred twenty-three".

Divisors: 1 433 4626331 2003201323