Base | Representation |
---|---|
bin | 101101100011000100011010… |
… | …011011101111010100011001 |
3 | 222021021121010112011001120211 |
4 | 231203010122123233110121 |
5 | 202224033440330211212 |
6 | 1550014355024251121 |
7 | 60123534141631555 |
oct | 5543043233572431 |
9 | 867247115131524 |
10 | 200322013132057 |
11 | 589130a8035573 |
12 | 1a5738b8a70aa1 |
13 | 87a1391889acb |
14 | 37678cc564865 |
15 | 1825c7e0c29a7 |
hex | b6311a6ef519 |
200322013132057 has 2 divisors, whose sum is σ = 200322013132058. Its totient is φ = 200322013132056.
The previous prime is 200322013131991. The next prime is 200322013132097. The reversal of 200322013132057 is 750231310223002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 168592461987856 + 31729551144201 = 12984316^2 + 5632899^2 .
It is a cyclic number.
It is not a de Polignac number, because 200322013132057 - 239 = 199772257318169 is a prime.
It is not a weakly prime, because it can be changed into another prime (200322013132097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100161006566028 + 100161006566029.
It is an arithmetic number, because the mean of its divisors is an integer number (100161006566029).
Almost surely, 2200322013132057 is an apocalyptic number.
It is an amenable number.
200322013132057 is a deficient number, since it is larger than the sum of its proper divisors (1).
200322013132057 is an equidigital number, since it uses as much as digits as its factorization.
200322013132057 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15120, while the sum is 31.
Adding to 200322013132057 its reverse (750231310223002), we get a palindrome (950553323355059).
The spelling of 200322013132057 in words is "two hundred trillion, three hundred twenty-two billion, thirteen million, one hundred thirty-two thousand, fifty-seven".
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