200323130012113 has 4 divisors (see below), whose sum is σ = 200359665332208. Its totient is φ = 200286594692020.

The previous prime is 200323130012099. The next prime is 200323130012141. The reversal of 200323130012113 is 311210031323002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200323130012113 - 2¹³ = 200323130003921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200323130019113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18267651823 + ... + 18267662788.

It is an arithmetic number, because the mean of its divisors is an integer number (50089916333052).

Almost surely, 2^{200323130012113} is an apocalyptic number.

It is an amenable number.

200323130012113 is a deficient number, since it is larger than the sum of its proper divisors (36535320095).

200323130012113 is an equidigital number, since it uses as much as digits as its factorization.

200323130012113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36535320094.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 200323130012113 its reverse (311210031323002), we get a palindrome (511533161335115).

The spelling of 200323130012113 in words is "two hundred trillion, three hundred twenty-three billion, one hundred thirty million, twelve thousand, one hundred thirteen".