Base | Representation |
---|---|
bin | 1011101010010000110… |
… | …0011010010001110011 |
3 | 201011001212110120120011 |
4 | 2322210030122101303 |
5 | 11240230220244103 |
6 | 232005513355351 |
7 | 20321124132136 |
oct | 2724414322163 |
9 | 634055416504 |
10 | 200323212403 |
11 | 77a5825a496 |
12 | 329a7a08b57 |
13 | 15b76286612 |
14 | 99a4db821d |
15 | 5326a1ad6d |
hex | 2ea431a473 |
200323212403 has 2 divisors, whose sum is σ = 200323212404. Its totient is φ = 200323212402.
The previous prime is 200323212389. The next prime is 200323212407. The reversal of 200323212403 is 304212323002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200323212403 - 217 = 200323081331 is a prime.
It is not a weakly prime, because it can be changed into another prime (200323212407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100161606201 + 100161606202.
It is an arithmetic number, because the mean of its divisors is an integer number (100161606202).
Almost surely, 2200323212403 is an apocalyptic number.
200323212403 is a deficient number, since it is larger than the sum of its proper divisors (1).
200323212403 is an equidigital number, since it uses as much as digits as its factorization.
200323212403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 22.
Adding to 200323212403 its reverse (304212323002), we get a palindrome (504535535405).
The spelling of 200323212403 in words is "two hundred billion, three hundred twenty-three million, two hundred twelve thousand, four hundred three".
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