Base | Representation |
---|---|
bin | 1001000111000010100101… |
… | …01001001111001101001001 |
3 | 2121221010222011022112021220 |
4 | 10203201102221033031021 |
5 | 10111210304141313231 |
6 | 110335030250152253 |
7 | 4135226145330240 |
oct | 443412251171511 |
9 | 77833864275256 |
10 | 20033114010441 |
11 | 6423aa5662214 |
12 | 22b6675422689 |
13 | b2416486ac5c |
14 | 4d38720a9957 |
15 | 24b192074896 |
hex | 123852a4f349 |
20033114010441 has 8 divisors (see below), whose sum is σ = 30526649920704. Its totient is φ = 11447493720240.
The previous prime is 20033114010439. The next prime is 20033114010463. The reversal of 20033114010441 is 14401041133002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 20033114010441 - 21 = 20033114010439 is a prime.
It is not an unprimeable number, because it can be changed into a prime (20033114010401) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 476978904990 + ... + 476978905031.
It is an arithmetic number, because the mean of its divisors is an integer number (3815831240088).
Almost surely, 220033114010441 is an apocalyptic number.
20033114010441 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
It is an amenable number.
20033114010441 is a deficient number, since it is larger than the sum of its proper divisors (10493535910263).
20033114010441 is an equidigital number, since it uses as much as digits as its factorization.
20033114010441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 953957810031.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 20033114010441 its reverse (14401041133002), we get a palindrome (34434155143443).
The spelling of 20033114010441 in words is "twenty trillion, thirty-three billion, one hundred fourteen million, ten thousand, four hundred forty-one".
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