Base | Representation |
---|---|
bin | 101101100011001110101111… |
… | …010001010010001100110010 |
3 | 222021022122202012021222002211 |
4 | 231203032233101102030302 |
5 | 202224224142113143442 |
6 | 1550023431121202334 |
7 | 60124405655601160 |
oct | 5543165721221462 |
9 | 867278665258084 |
10 | 200333100131122 |
11 | 58917877395012 |
12 | 1a575a91a903aa |
13 | 87a243a82549a |
14 | 3768260c00230 |
15 | 18261cc5e9617 |
hex | b633af452332 |
200333100131122 has 8 divisors (see below), whose sum is σ = 343428171653376. Its totient is φ = 85857042913332.
The previous prime is 200333100131117. The next prime is 200333100131149. The reversal of 200333100131122 is 221131001333002.
200333100131122 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 200333100131093 and 200333100131102.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7154753576098 + ... + 7154753576125.
It is an arithmetic number, because the mean of its divisors is an integer number (42928521456672).
Almost surely, 2200333100131122 is an apocalyptic number.
200333100131122 is a deficient number, since it is larger than the sum of its proper divisors (143095071522254).
200333100131122 is a wasteful number, since it uses less digits than its factorization.
200333100131122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14309507152232.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 200333100131122 its reverse (221131001333002), we get a palindrome (421464101464124).
The spelling of 200333100131122 in words is "two hundred trillion, three hundred thirty-three billion, one hundred million, one hundred thirty-one thousand, one hundred twenty-two".
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