Base | Representation |
---|---|
bin | 101101100011001110110101… |
… | …111100011111110000110001 |
3 | 222021022200001000000200221002 |
4 | 231203032311330133300301 |
5 | 202224224404300402121 |
6 | 1550023450201411345 |
7 | 60124411515524516 |
oct | 5543166574376061 |
9 | 867280030020832 |
10 | 200333212122161 |
11 | 58917924626598 |
12 | 1a575b03499b55 |
13 | 87a2457aa6b81 |
14 | 3768271a3330d |
15 | 18261d736be0b |
hex | b633b5f1fc31 |
200333212122161 has 2 divisors, whose sum is σ = 200333212122162. Its totient is φ = 200333212122160.
The previous prime is 200333212122139. The next prime is 200333212122187. The reversal of 200333212122161 is 161221212333002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 146532380763136 + 53800831359025 = 12105056^2 + 7334905^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-200333212122161 is a prime.
It is not a weakly prime, because it can be changed into another prime (200333212122961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100166606061080 + 100166606061081.
It is an arithmetic number, because the mean of its divisors is an integer number (100166606061081).
Almost surely, 2200333212122161 is an apocalyptic number.
It is an amenable number.
200333212122161 is a deficient number, since it is larger than the sum of its proper divisors (1).
200333212122161 is an equidigital number, since it uses as much as digits as its factorization.
200333212122161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 200333212122161 its reverse (161221212333002), we get a palindrome (361554424455163).
The spelling of 200333212122161 in words is "two hundred trillion, three hundred thirty-three billion, two hundred twelve million, one hundred twenty-two thousand, one hundred sixty-one".
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