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2003344201361 = 7925358787359
BaseRepresentation
bin11101001001110000100…
…111101001011010010001
321002111222111112212210202
4131021300213221122101
5230310322103420421
64132153522504545
7264510510514166
oct35116047513221
97074874485722
102003344201361
11702682635868
12284317b05155
13116bb7351649
146cd68a9406d
15371a18b210b
hex1d2709e9691

2003344201361 has 4 divisors (see below), whose sum is σ = 2028702988800. Its totient is φ = 1977985413924.

The previous prime is 2003344201351. The next prime is 2003344201363. The reversal of 2003344201361 is 1631024433002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2003344201361 - 210 = 2003344200337 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2003344201363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12679393601 + ... + 12679393758.

It is an arithmetic number, because the mean of its divisors is an integer number (507175747200).

Almost surely, 22003344201361 is an apocalyptic number.

It is an amenable number.

2003344201361 is a deficient number, since it is larger than the sum of its proper divisors (25358787439).

2003344201361 is an equidigital number, since it uses as much as digits as its factorization.

2003344201361 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25358787438.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 2003344201361 its reverse (1631024433002), we get a palindrome (3634368634363).

The spelling of 2003344201361 in words is "two trillion, three billion, three hundred forty-four million, two hundred one thousand, three hundred sixty-one".

Divisors: 1 79 25358787359 2003344201361