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20034000401 = 60733004943
BaseRepresentation
bin10010101010000111…
…101001011000010001
31220201012111200000212
4102222013221120101
5312012201003101
613111542053505
71306314123302
oct225207513021
956635450025
1020034000401
118550742028
123a7141a295
131b7375070c
14d80a167a9
157c3c351bb
hex4aa1e9611

20034000401 has 4 divisors (see below), whose sum is σ = 20067005952. Its totient is φ = 20000994852.

The previous prime is 20034000379. The next prime is 20034000403. The reversal of 20034000401 is 10400043002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20034000401 - 214 = 20033984017 is a prime.

It is a super-2 number, since 2×200340004012 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20034000403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16501865 + ... + 16503078.

It is an arithmetic number, because the mean of its divisors is an integer number (5016751488).

Almost surely, 220034000401 is an apocalyptic number.

It is an amenable number.

20034000401 is a deficient number, since it is larger than the sum of its proper divisors (33005551).

20034000401 is an equidigital number, since it uses as much as digits as its factorization.

20034000401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33005550.

The product of its (nonzero) digits is 96, while the sum is 14.

Adding to 20034000401 its reverse (10400043002), we get a palindrome (30434043403).

The spelling of 20034000401 in words is "twenty billion, thirty-four million, four hundred one", and thus it is an aban number.

Divisors: 1 607 33004943 20034000401