2003424113 has 4 divisors (see below), whose sum is σ = 2004334080. Its totient is φ = 2002514148.

The previous prime is 2003424107. The next prime is 2003424127. The reversal of 2003424113 is 3114243002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2003424113 - 2¹² = 2003420017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2003424103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 451673 + ... + 456086.

It is an arithmetic number, because the mean of its divisors is an integer number (501083520).

Almost surely, 2^2003424113 is an apocalyptic number.

It is an amenable number.

2003424113 is a deficient number, since it is larger than the sum of its proper divisors (909967).

2003424113 is an equidigital number, since it uses as much as digits as its factorization.

2003424113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 909966.

The product of its (nonzero) digits is 576, while the sum is 20.

The square root of 2003424113 is about 44759.6259256040. The cubic root of 2003424113 is about 1260.6396586255.

Adding to 2003424113 its reverse (3114243002), we get a palindrome (5117667115).

The spelling of 2003424113 in words is "two billion, three million, four hundred twenty-four thousand, one hundred thirteen".