Base | Representation |
---|---|
bin | 1001000111000100110100… |
… | …01001000001000000110011 |
3 | 2121221021001202102002112021 |
4 | 10203202122021001000303 |
5 | 10111220233230221001 |
6 | 110335345300012311 |
7 | 4135300652116156 |
oct | 443423211010063 |
9 | 77837052362467 |
10 | 20034313523251 |
11 | 6424560765a15 |
12 | 22b694b091097 |
13 | b242c6221751 |
14 | 4d394750dc9d |
15 | 24b212515ba1 |
hex | 12389a241033 |
20034313523251 has 2 divisors, whose sum is σ = 20034313523252. Its totient is φ = 20034313523250.
The previous prime is 20034313523171. The next prime is 20034313523303. The reversal of 20034313523251 is 15232531343002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20034313523251 - 221 = 20034311426099 is a prime.
It is not a weakly prime, because it can be changed into another prime (20034313527251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10017156761625 + 10017156761626.
It is an arithmetic number, because the mean of its divisors is an integer number (10017156761626).
Almost surely, 220034313523251 is an apocalyptic number.
20034313523251 is a deficient number, since it is larger than the sum of its proper divisors (1).
20034313523251 is an equidigital number, since it uses as much as digits as its factorization.
20034313523251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 34.
Adding to 20034313523251 its reverse (15232531343002), we get a palindrome (35266844866253).
The spelling of 20034313523251 in words is "twenty trillion, thirty-four billion, three hundred thirteen million, five hundred twenty-three thousand, two hundred fifty-one".
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