Base | Representation |
---|---|
bin | 1011101010010110000… |
… | …0000100111100101011 |
3 | 201011010101201212121102 |
4 | 2322211200010330223 |
5 | 11240301324121011 |
6 | 232012015432015 |
7 | 20321511431015 |
oct | 2724540047453 |
9 | 634111655542 |
10 | 200345145131 |
11 | 77a6967a90a |
12 | 329b322560b |
13 | 15b7a995671 |
14 | 99a7c871b5 |
15 | 53288ee73b |
hex | 2ea5804f2b |
200345145131 has 2 divisors, whose sum is σ = 200345145132. Its totient is φ = 200345145130.
The previous prime is 200345145113. The next prime is 200345145151. The reversal of 200345145131 is 131541543002.
Together with previous prime (200345145113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200345145131 - 230 = 199271403307 is a prime.
It is a super-2 number, since 2×2003451451312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 200345145094 and 200345145103.
It is not a weakly prime, because it can be changed into another prime (200345145151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100172572565 + 100172572566.
It is an arithmetic number, because the mean of its divisors is an integer number (100172572566).
Almost surely, 2200345145131 is an apocalyptic number.
200345145131 is a deficient number, since it is larger than the sum of its proper divisors (1).
200345145131 is an equidigital number, since it uses as much as digits as its factorization.
200345145131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 200345145131 its reverse (131541543002), we get a palindrome (331886688133).
The spelling of 200345145131 in words is "two hundred billion, three hundred forty-five million, one hundred forty-five thousand, one hundred thirty-one".
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