Search a number
-
+
2003502097 is a prime number
BaseRepresentation
bin111011101101011…
…0000010000010001
312011121221110012101
41313122300100101
513100344031342
6530450000401
7100435325662
oct16732602021
95147843171
102003502097
11938a19863
1247ab76101
1325c1023cc
1415012b369
15bad553b7
hex776b0411

2003502097 has 2 divisors, whose sum is σ = 2003502098. Its totient is φ = 2003502096.

The previous prime is 2003502043. The next prime is 2003502103. The reversal of 2003502097 is 7902053002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1252522881 + 750979216 = 35391^2 + 27404^2 .

It is a cyclic number.

It is not a de Polignac number, because 2003502097 - 227 = 1869284369 is a prime.

It is not a weakly prime, because it can be changed into another prime (2003502797) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001751048 + 1001751049.

It is an arithmetic number, because the mean of its divisors is an integer number (1001751049).

Almost surely, 22003502097 is an apocalyptic number.

It is an amenable number.

2003502097 is a deficient number, since it is larger than the sum of its proper divisors (1).

2003502097 is an equidigital number, since it uses as much as digits as its factorization.

2003502097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3780, while the sum is 28.

The square root of 2003502097 is about 44760.4970593491. The cubic root of 2003502097 is about 1260.6560153631.

Adding to 2003502097 its reverse (7902053002), we get a palindrome (9905555099).

It can be divided in two parts, 2003 and 502097, that added together give a square (504100 = 7102).

The spelling of 2003502097 in words is "two billion, three million, five hundred two thousand, ninety-seven".