200353649953 has 4 divisors (see below), whose sum is σ = 201066652548. Its totient is φ = 199640647360.

The previous prime is 200353649941. The next prime is 200353649989. The reversal of 200353649953 is 359946353002.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 359946353002 = 2 ⋅179973176501.

It can be written as a sum of positive squares in 2 ways, for example, as 76014901264 + 124338748689 = 275708^2 + 352617^2 .

It is a cyclic number.

It is not a de Polignac number, because 200353649953 - 2¹⁷ = 200353518881 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200353649897 and 200353649906.

It is not an unprimeable number, because it can be changed into a prime (200353649933) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 356500876 + ... + 356501437.

It is an arithmetic number, because the mean of its divisors is an integer number (50266663137).

Almost surely, 2^200353649953 is an apocalyptic number.

It is an amenable number.

200353649953 is a deficient number, since it is larger than the sum of its proper divisors (713002595).

200353649953 is an equidigital number, since it uses as much as digits as its factorization.

200353649953 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 713002594.

The product of its (nonzero) digits is 2624400, while the sum is 49.

It can be divided in two parts, 2003536 and 49953, that added together give a square (2053489 = 1433²).

The spelling of 200353649953 in words is "two hundred billion, three hundred fifty-three million, six hundred forty-nine thousand, nine hundred fifty-three".