Base | Representation |
---|---|
bin | 10010101010011000… |
… | …110001010101011001 |
3 | 1220201111221201211022 |
4 | 102222120301111121 |
5 | 312014323130213 |
6 | 13112222212225 |
7 | 1306400230664 |
oct | 225230612531 |
9 | 56644851738 |
10 | 20038489433 |
11 | 8553228776 |
12 | 3a72a24075 |
13 | 1b74662a51 |
14 | d814646db |
15 | 7c4320308 |
hex | 4aa631559 |
20038489433 has 16 divisors (see below), whose sum is σ = 21419513856. Its totient is φ = 18702427920.
The previous prime is 20038489411. The next prime is 20038489481. The reversal of 20038489433 is 33498483002.
It is a de Polignac number, because none of the positive numbers 2k-20038489433 is a prime.
It is a super-3 number, since 3×200384894333 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20038489483) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 329810 + ... + 385812.
It is an arithmetic number, because the mean of its divisors is an integer number (1338719616).
Almost surely, 220038489433 is an apocalyptic number.
20038489433 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
20038489433 is a deficient number, since it is larger than the sum of its proper divisors (1381024423).
20038489433 is a wasteful number, since it uses less digits than its factorization.
20038489433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56404.
The product of its (nonzero) digits is 497664, while the sum is 44.
The spelling of 20038489433 in words is "twenty billion, thirty-eight million, four hundred eighty-nine thousand, four hundred thirty-three".
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