Search a number
-
+
20038738423339 = 120566916620431
BaseRepresentation
bin1001000111001101000011…
…11000101010111000101011
32121221200111010122022022201
410203212201320222320223
510111303314014021324
6110341400325001031
74135515422132416
oct443464170527053
977850433568281
1020038738423339
116426421481939
1222b7784b53177
13b2484cb9231c
144d3c4706ab7d
1524b3c0c1c444
hex1239a1e2ae2b

20038738423339 has 4 divisors (see below), whose sum is σ = 20038756249440. Its totient is φ = 20038720597240.

The previous prime is 20038738423321. The next prime is 20038738423351. The reversal of 20038738423339 is 93332483783002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20038738423339 - 25 = 20038738423307 is a prime.

It is a super-5 number, since 5×200387384233395 (a number of 68 digits) contains 55555 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 20038738423339.

It is not an unprimeable number, because it can be changed into a prime (20038738423309) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7104547 + ... + 9515884.

It is an arithmetic number, because the mean of its divisors is an integer number (5009689062360).

Almost surely, 220038738423339 is an apocalyptic number.

20038738423339 is a deficient number, since it is larger than the sum of its proper divisors (17826101).

20038738423339 is a wasteful number, since it uses less digits than its factorization.

20038738423339 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17826100.

The product of its (nonzero) digits is 15676416, while the sum is 55.

The spelling of 20038738423339 in words is "twenty trillion, thirty-eight billion, seven hundred thirty-eight million, four hundred twenty-three thousand, three hundred thirty-nine".

Divisors: 1 1205669 16620431 20038738423339