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200413242281251 is a prime number
BaseRepresentation
bin101101100100011001011000…
…000111010100110100100011
3222021121022121102220000102101
4231210121120013110310203
5202232032310011000001
61550124323353431231
760133243654616506
oct5544313007246443
9867538542800371
10200413242281251
115894886256163a
121a58951940b517
1387a9b7023b1ac
14376c0a47bd13d
15182831d2e6a01
hexb646581d4d23

200413242281251 has 2 divisors, whose sum is σ = 200413242281252. Its totient is φ = 200413242281250.

The previous prime is 200413242281243. The next prime is 200413242281309. The reversal of 200413242281251 is 152182242314002.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 200413242281251 - 23 = 200413242281243 is a prime.

It is a super-2 number, since 2×2004132422812512 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 200413242281251.

It is not a weakly prime, because it can be changed into another prime (200413242281221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100206621140625 + 100206621140626.

It is an arithmetic number, because the mean of its divisors is an integer number (100206621140626).

Almost surely, 2200413242281251 is an apocalyptic number.

200413242281251 is a deficient number, since it is larger than the sum of its proper divisors (1).

200413242281251 is an equidigital number, since it uses as much as digits as its factorization.

200413242281251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 61440, while the sum is 37.

Adding to 200413242281251 its reverse (152182242314002), we get a palindrome (352595484595253).

The spelling of 200413242281251 in words is "two hundred trillion, four hundred thirteen billion, two hundred forty-two million, two hundred eighty-one thousand, two hundred fifty-one".